Question #ba70b - Socratic Problem 1 Let { ( (x_1,y_1)= (3,5)), ( (x_2,y_2)= (-9,5)):} By Slope Formula, m= {y_2-y_1} {x_2-x_1}= {5-5} {-9-3}=0 By Point-Slope Form y-y_1=m (x-x_1), we have the equation y-5=0 (x-3)=0 => y=5 Problem 2 Let (x_1,y_1)= (2, (2)^3-10)= (2,-2) By rewriting the equation in Slope-Intercept Form, 3x-2y+5=0 => y=3 2x+5 2 => Slope =3 2 By taking the negative reciprocal (since perpendcular), m=-2 3
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Question #a77d0 - Socratic The way to solve this question is to first find the slope using the two points given and then use that slope like you would in point slope form The Final equation : #y + 2 = 2x - 12#
Write the equation of the line passing through the givin points write . . . the equation of a line in standard form is ¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯∣∣ ∣ 2 2Ax +By = C 2 2∣∣ ∣ −−−−−−−−−−−−−−−−− where A is a positive integer and B, C are integers the equation of a line in slope-intercept form is ∙ xy = mx + b where m is the slope and b the y-intercept to calculate m use the gradient
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