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  • Chemical Equilibrium: Co(H2O)62+ + 4 Cl- ---- gt; CoCl42- 6 H2O
    The discussion revolves around the chemical equilibrium of the reaction between Co (H2O)6 2+ and Cl - to form CoCl 42- and water Participants are exploring how to demonstrate that the system is not at equilibrium initially and how to calculate the final concentrations of each species at equilibrium, including the use of the equilibrium constant K Some participants suggest demonstrating that
  • How Do You Convert Energy from J kg to kJ mol? - Physics Forums
    The discussion revolves around converting energy values from joules per kilogram to kilojoules per mole, specifically using a value of 553 x 10^5 J kg The subject area includes thermodynamics and stoichiometry related to energy calculations in chemistry Exploratory, Assumption checking, Conceptual clarification Participants discuss the conversion of joules to kilojoules and the need for
  • Relation between mole, volume and pressure fraction
    Homework Statement If mole fraction, pressure fraction and volume fraction are denoted by X mol , X p, X V respectively, of a gaseous component, then what is the relation between them? Homework Equations mole fraction = mole of component total moles pressure fraction = pressure of component total pressure volume fraction = volume of component total volume The Attempt at a Solution Well
  • Convert J mol k into atm cm^3 mol k - Physics Forums
    For 3 feet into inches: 3 x [ft x 12 inch 1 ft], the ft's cancel and you do 3 x 12 = 36 inches But for converting J mol k to atm mol k I am not sure what to do I know these are the conversion factors: 1 J = Nm 1 atm = 101325 Pa Pa = N m^2 1 m^3 = 1 x 10^6 cm^3 But I am trying to reconcile how Joules can be expressed in terms of pressure x
  • How do I convert from kJ kg to kJ mol? - Physics Forums
    The conversion of isobutanol's heat of combustion from kJ kg to kJ mol involves using its molar mass of 74 g mol The heat of combustion is 35 981 kJ per gram, which means that burning one mole (74 grams) yields 74 times this amount Therefore, the heat of combustion for isobutanol in kJ mol is calculated as 35 981 kJ multiplied by 74, resulting in a total of 2665 654 kJ mol Ability to
  • Equilibrium Physics Help: Calculating Kp for a Hydrogen Iodide Reaction
    Homework Statement In an experiment , b mole of hydrogen iodide were put into a sealed vessel under pressure p At equilibrium, x mole of the hydrogen iodide had dissociated , the reaction being represented by the following equation , Express in terms of b and x of Kp Homework
  • Calculating the Mass of a Precipitate • Physics Forums
    So to convert the number of moles of solute to moles of precipitate we multiply 0 01088 m x 1 2 So number of moles of precipitate present is 0 00544 mol We now convert this to mass of precipitate by multiplying the number of moles of precipitate by it's formula mass (262 855 g mol) giving 1 4299 g So
  • Calculte the Energy of 1 mole of photons - Help - Physics Forums
    The discussion revolves around calculating the energy of one mole of photons from yellow laser light with a specified wavelength of 570 nm The problem is situated within the context of quantum physics and energy calculations related to photons The original poster attempts to calculate the energy of a single photon and convert it to kilojoules, but expresses confusion over the final result
  • Deriving Avogadros Number without using mol - Physics Forums
    The discussion revolves around deriving Avogadro's number without referencing the concept of a mole Participants explore historical and experimental contexts, questioning how early scientists, particularly Robert Millikan, understood the quantity of electrons in a mole before Avogadro's number was quantified Some participants express frustration that explanations of Avogadro's number always
  • Calculating mass of oxygen in CaCO3. . . . • Physics Forums
    Homework Statement What would be the mass of oxygen in 2 5 x 102 g in CaCO3? Given: Mass 2 5 x 102 Molar Mass of CaCO3 which is 100 09 g mol Homework Equations mo=molar mass x number of o The Attempt at a Solution mo=100 09 g mol x 3 mo=300 27 g of oxygen Can someone tell me if I got this





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